Thursday, September 7, 2017

linear algebra lecture 21 09/07/2017

特征值和特征向量

Ax = lamda*x
what are x and lamda for prpojection matrix
any x in the plane, Px = x ; lamda = 1
any x perpendicular to the plane, Px = 0x, lamda = 0

How to solve Ax = lamda * x

(A-lamda*I)*x = 0
A-lamda*I 一定要singular,不然没解
所以行列式为0

如果矩阵+3I, eigenvector don't change, eigen value +3


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